Întrebare
(5,(4)) la puterea 18 :(49 supra 9) la puterea 17; 0,(4):2;4 x (0,5) la puterea2; (12 supra 5 + 0,(3))
Întrebare a fost pusă de: USER5491
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104 Răspunsuri
Răspuns (104)
[5,(4)]^18:(49/9)^17
(5 4/9)^18:(49/9)^17
(49/9)^18:(49/9)^17=49/9
0,(4):2=4/9:2/1=4/9x1/2=4/18=2/9
4x(0,5)^2=4x(1/2)^2=4x1/4=4/4=1
12/5+0,(3)=12/5+3/9=12/5+1/3=36/15+5/15=41/15
(5 4/9)^18:(49/9)^17
(49/9)^18:(49/9)^17=49/9
0,(4):2=4/9:2/1=4/9x1/2=4/18=2/9
4x(0,5)^2=4x(1/2)^2=4x1/4=4/4=1
12/5+0,(3)=12/5+3/9=12/5+1/3=36/15+5/15=41/15