Ajutorr!! va rog!!
Ce cantitate de dioxid de sulf contine aceeasi masa de sulf ca si 2 moli de trioxid de sulf?

niu= m/miu⇒m=niu*miu
M SO3= 32+3*16= 32+48=80⇒miu= 80g/mol
m=2*80=160g SO3
In 80g SO3..................32g S
   160g SO3.................x g S
x=180*32/ 80=64g S in 2moliSO3
MSO2=32+2*16= 64⇒miu= 64g/mol
In 64g SO2..............32g S
    y g SO2................64g S
    y= 64*64/ 32=128g SO2