Question
(-8x+5)*-(2x-10)*
sa fait combien?
merci!!
sa fait combien?
merci!!
Asked by: USER9877
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60 Answers
Answer (60)
Bonjour Noemiebordron
[tex](-8x+5)^2-(2x-10)^2\\\\=[(-8x)^2+2\times(-8x)\times5+5^2[-[(2x)^2-2\times2x\times10+10^2]\\\\=(64x^2-80x+25)-(4x^2-40x+100)\\\\=64x^2-80x+25-4x^2+40x-100\\\\\boxed{=60x^2-40x-75}[/tex]
[tex](-8x+5)^2-(2x-10)^2\\\\=[(-8x)^2+2\times(-8x)\times5+5^2[-[(2x)^2-2\times2x\times10+10^2]\\\\=(64x^2-80x+25)-(4x^2-40x+100)\\\\=64x^2-80x+25-4x^2+40x-100\\\\\boxed{=60x^2-40x-75}[/tex]