résoudre l'équation : j) : 3 diviser par x au carré -9 = 1/ x-3

By: USER7693
28 Agustus 2025 mathematiques 5 minutes
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Grade: Education Subject: mathematiques
résoudre l'équation : j) : 3 diviser par x au carré -9 = 1/ x-3
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3/(x²-9)=1/(x-3)
Donc
3/(x²-9)-1/(x-3)=0
3/(x²-9)-(x+3)/(x²-9)=0
(3-x-3)/(x²-9)=0
x/(x²-9)=0
Un quotient est nul si le numérateur est nul donc x=0
Answered on 28 Agustus 2025

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Exercice 3
Voici un programme de calcul.
Choisir un nombre.
Additionner 3.
Multiplier par le nombre choisi au départ.
Soustraire le carré du nombre choisi au départ.
1. Quel nombre obtient-on si l'on choisit 4 comme nombre de départ ?
Merci d’avance

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