Question
3-(4a-7)=6-5(12-8a) ??
-4(a+5)-6(12a-30)=0 ??
-4(a+5)-6(12a-30)=0 ??
Asked by: USER9292
53 Viewed
53 Answers
Answer (53)
3-(4a-7)=6-5(12-8a)
3 - 4a + 7 = 6 - 60 + 40a
- 4a - 40a = 6 - 60 - 3 - 7
- 44a = - 64
a = 64/44
a = 4 x 16 / 4 x 11
a = 16/11
- 4 (a + 5) - 6 (12a - 30) = 0
- 4a - 20 - 72a + 180 = 0
- 4a - 72a = - 180 + 20
- 76a = - 160
a = 4 x - 40 / 4 x - 19
a = 40/19
3 - 4a + 7 = 6 - 60 + 40a
- 4a - 40a = 6 - 60 - 3 - 7
- 44a = - 64
a = 64/44
a = 4 x 16 / 4 x 11
a = 16/11
- 4 (a + 5) - 6 (12a - 30) = 0
- 4a - 20 - 72a + 180 = 0
- 4a - 72a = - 180 + 20
- 76a = - 160
a = 4 x - 40 / 4 x - 19
a = 40/19
-4(a+5) - 6(12a -30) = 0
-4a -20 -72a +180 = 0
-76a + 160=0
-76a = - 160
a = 160/76 = 80 / 38 = 40 / 19
3-(4a-7)=6-5(12-8a)
3 - 4a +7 = 6 -60 +40 a
10 -4a = -54 + 40a
-4a -40 a = -54 -10
-44a = -64
a = 64/44 = 32/22 = 16/11
-4a -20 -72a +180 = 0
-76a + 160=0
-76a = - 160
a = 160/76 = 80 / 38 = 40 / 19
3-(4a-7)=6-5(12-8a)
3 - 4a +7 = 6 -60 +40 a
10 -4a = -54 + 40a
-4a -40 a = -54 -10
-44a = -64
a = 64/44 = 32/22 = 16/11