Question
Comment résoudre l'équation (j'avais oublié 1 k)
-3k+0,2=5/7k-4,8
-3k+0,2=5/7k-4,8
Asked by: USER3363
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71 Answers
Answer (71)
Bonsoir Ririne
[tex]-3k+0,2=\dfrac{5}{7}k-4,8\\\\-3k-\dfrac{5}{7}k=-4,8-0,2\\\\-\dfrac{21}{7}k-\dfrac{5}{7}k=-5\\\\-\dfrac{26}{7}k=-5\\\\\dfrac{26}{7}k=5[/tex]
[tex]k=5\times\dfrac{7}{26}\\\\\boxed{k=\dfrac{35}{26}}[/tex]
[tex]-3k+0,2=\dfrac{5}{7}k-4,8\\\\-3k-\dfrac{5}{7}k=-4,8-0,2\\\\-\dfrac{21}{7}k-\dfrac{5}{7}k=-5\\\\-\dfrac{26}{7}k=-5\\\\\dfrac{26}{7}k=5[/tex]
[tex]k=5\times\dfrac{7}{26}\\\\\boxed{k=\dfrac{35}{26}}[/tex]