Question
A=13/4 -7/4 *5/6 B=2 - 8/13 * 8/5 C=5/72 - (2/3 +1/12 ) Calculer et donner le résultat des expressions sous la forme la plus simple. (écrire les étapes intermédiaires)
Asked by: USER1488
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[tex]A = \frac{13}{4} - \frac{7}{4} *\frac{5}{6} = \frac{13}{4} - \frac{7*5}{4*6} = \frac{13}{4} - \frac{35}{24} = \frac{6*13}{6*4} - \frac{35}{24} = \frac{78}{24} - \frac{35}{24} = \frac{43}{24} [/tex]
[tex]B = 2- \frac{8}{13} * \frac{8}{5} = 2- \frac{8*8}{13*5} = 2- \frac{64}{65} = \frac{65*2}{65*1} - \frac{64}{65} = \frac{130}{65} - \frac{64}{65} = \frac{66}{65} [/tex]
[tex]C = \frac{5}{72} - ( \frac{2}{3} + \frac{1}{12} ) = \frac{5}{72} - ( \frac{4*2}{4*3} + \frac{1}{12} ) = \frac{5}{72} - ( \frac{8}{12} + \frac{1}{12} ) = \frac{5}{72} - \frac{9}{12} = \frac{5}{72} - \frac{6*9}{6*12} = \frac{5}{72} - \frac{54}{72} = -\frac{49}{72} [/tex]
[tex]B = 2- \frac{8}{13} * \frac{8}{5} = 2- \frac{8*8}{13*5} = 2- \frac{64}{65} = \frac{65*2}{65*1} - \frac{64}{65} = \frac{130}{65} - \frac{64}{65} = \frac{66}{65} [/tex]
[tex]C = \frac{5}{72} - ( \frac{2}{3} + \frac{1}{12} ) = \frac{5}{72} - ( \frac{4*2}{4*3} + \frac{1}{12} ) = \frac{5}{72} - ( \frac{8}{12} + \frac{1}{12} ) = \frac{5}{72} - \frac{9}{12} = \frac{5}{72} - \frac{6*9}{6*12} = \frac{5}{72} - \frac{54}{72} = -\frac{49}{72} [/tex]