Question
Salut, j'ai besoin d'aides pour cela svp:
Factorisation: en utilisant (a+b)(a-b)
[tex] {(x + 6)}^{2} - {(3x - 1)}^{2} [/tex]
Factoriser:
[tex](x + 3)(3 - 2x) - (x + 3)(5 + x)[/tex]
Factorisation: en utilisant (a+b)(a-b)
[tex] {(x + 6)}^{2} - {(3x - 1)}^{2} [/tex]
Factoriser:
[tex](x + 3)(3 - 2x) - (x + 3)(5 + x)[/tex]
Asked by: USER1958
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221 Answers
Answer (221)
bonjour
( x+ 6 )² - ( 3 x - 1 )²
= ( x + 6 - 3 x + 1 ) ( x + 6 + 3 x - 1 )
= ( - 2 x + 7 ) ( 4 x + 5 )
( x + 3 ) ( 3 - 2 x ) - ( x + 3 ) ( 5 + x )
= ( x + 3 ) ( 3 - 2 x - 5 - x )
= ( x + 3 ) ( - 3 x - 2 )
Réponse :
(x+6)²-(3x-1)²
=((x+6)+(3x-1))((x+6)-(3x-1))
=(x+6+3x-1)(x+6-3x+1)
=(4x+5)(-2x+7)
(x+3)(3-2x)-(x+3)(5+x)
=(x+3)((3-2x)-(5+x))
=(x+3)(3-2x-5-x)
=(x+3)(-3x-2)