developper et reduire (2x+3) ^{2} -(x-4) ^{2} 

By: USER8551
25 Agustus 2025 mathematiques 5 minutes
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Question

Grade: Education Subject: mathematiques
developper et reduire (2x+3) ^{2} -(x-4) ^{2} 

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Answer (91)

Best Answer
(102)
 (2x+3)² -(x-4)²
=(2x+3-x+4)(2x+3+x-4)
=(x+7)(3x-1)
=3x²+20x-7

Answered on 25 Agustus 2025

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