Find the equation for the line perpendicular to 2xty=3 and passes through the point (2,-5).

Answer:

The equation of the line would be y = -1/2x - 4

Step-by-step explanation:

First we must find the slope of the first line. We do this by solving for y.

2x + y = 3

y = -2x + 3

Now we take the slope of 2 and find the perpendicular slope by taking the opposite and reciprocal. So, 2 becomes -1/2. Using this and the given point in point-slope form, we can find the equation.

y - y1 = m(x - x1)

y + 5 = -1/2(x - 2)

y + 5 = -1/2x + 1

y = -1/2x - 4