the width of a rectangular garden is 6 meter less than the length of the length of the garden. if the area of the garden is 78 square meters . what are the dimensions of the dimensions of the nearest tenth of a meter

Let's assume

width =w

length=l

we are given

The width of a rectangular garden is 6 meter less than the length of the length of the garden

so, we have

[tex] w=l-6 [/tex]

we know that

Area = length*width

[tex] A=l*w [/tex]

we are given

the area of the garden is 78 square meters

so, we can set A=78

[tex] 78=l*w [/tex]

now, we can plug for w

[tex] 78=l*(l-6) [/tex]

[tex] l^2-6l-78=0 [/tex]

now, we can solve for l

we get

[tex] l=12.3 [/tex]

now, we can find w

[tex] w=12.3-6 [/tex]

[tex] w=6.3 [/tex]

so, dimensions are

length is 12.3m

width is 6.3m................Answer