Someone plz help me!

Do the sqrt. of 2, the sqrt. of 2, and 2 make a right triangle?

These values can make a right triangle.

Here's how: if the two legs have a length of [tex] \sqrt{2} [/tex], and the hypotenuse is 2, the math checks out.

Let's use the Pythagorean theorem:

[tex] a^{2} +b^{2} =c^{2} [/tex]

a and b represent the leg lengths, whereas c represents the hypotenuse length:

[tex] (\sqrt{2})^{2}+(\sqrt{2})^{2} =(2)^{2} [/tex]

Then we simplify:

[tex] 2+2=4 [/tex]

And this is indeed true.