Question
Which of the following is the equation of the line that is perpendicular to y=−18x−2 and goes through the point (-2,-3)?
Asked by: USER6622
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Answer (120)
Given that the equation of the line is:
y=-18x-2
the equation is in the form of y=mx+c, where m is the slope. Thus the slope of equation is -18. The line perpendicular to this equation has a slope of 1/18, hence the equation will be given by the formula:
m(x-x1)=y-y1
given that the line passes through point (-2,-3) the equation of the line will be:
1/18(x--2)=y-(-3)
1/18(x+2)=y+3
simplifying this gives us:
y=1/18x+1/9+3
y=1/18x6+3 1/9
y=-18x-2
the equation is in the form of y=mx+c, where m is the slope. Thus the slope of equation is -18. The line perpendicular to this equation has a slope of 1/18, hence the equation will be given by the formula:
m(x-x1)=y-y1
given that the line passes through point (-2,-3) the equation of the line will be:
1/18(x--2)=y-(-3)
1/18(x+2)=y+3
simplifying this gives us:
y=1/18x+1/9+3
y=1/18x6+3 1/9