Amaya and bo each roll a fair, ordinary six-sided die with the numbers $1,2,3,4,5,6$ on the sides. what is the probability that amaya rolls a greater number than bo? enter your answer as a fraction in simplified form.

On the added picture is given a table of all possible die rolls, for example, under a pair (2,3) you mean that Bo rolls 2 on a die and Amaya rolls 3.

All red shaded cells responds to those choices, when Amaya rolls more than Bo.

Let's count: all possible rolls make up 36 choices and red shaded rolls make up 15 choices, then the probabiliry is

[tex] \dfrac{15}{36} = \dfrac{5}{12} [/tex].

Answer: [tex]\dfrac{5}{12} [/tex].